chapter-four/0200~0299/0230.Kth-Smallest-Element-in-a-BST

230. Kth Smallest Element in a BST

题目

Given a binary search tree, write a function kthSmallest to find the kth smallest element in it.

Note: You may assume k is always valid, 1 ≤ k ≤ BST's total elements.

Example 1:

Input: root = [3,1,4,null,2], k = 1
   3
  / \
 1   4
  \
   2
Output: 1

Example 2:

Input: root = [5,3,6,2,4,null,null,1], k = 3
       5
      / \
     3   6
    / \
   2   4
  /
 1
Output: 3

Follow up:What if the BST is modified (insert/delete operations) often and you need to find the kth smallest frequently? How would you optimize the kthSmallest routine?

题目大意

给定一个二叉搜索树,编写一个函数 kthSmallest 来查找其中第 k 个最小的元素。你可以假设 k 总是有效的,1 ≤ k ≤ 二叉搜索树元素个数。

解题思路

  • 由于二叉搜索树有序的特性,所以中根遍历它,遍历到第 K 个数的时候就是结果

代码

package leetcode /** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */ func kthSmallest(root *TreeNode, k int) int { res, count := 0, 0 inorder230(root, k, &count, &res) return res } func inorder230(node *TreeNode, k int, count *int, ans *int) { if node != nil { inorder230(node.Left, k, count, ans) *count++ if *count == k { *ans = node.Val return } inorder230(node.Right, k, count, ans) } }