chapter-four/0200~0299/0230.Kth-Smallest-Element-in-a-BST
230. Kth Smallest Element in a BST
题目
Given a binary search tree, write a function kthSmallest to find the kth smallest element in it.
Note: You may assume k is always valid, 1 ≤ k ≤ BST's total elements.
Example 1:
Input: root = [3,1,4,null,2], k = 1
3
/ \
1 4
\
2
Output: 1
Example 2:
Input: root = [5,3,6,2,4,null,null,1], k = 3
5
/ \
3 6
/ \
2 4
/
1
Output: 3
Follow up:What if the BST is modified (insert/delete operations) often and you need to find the kth smallest frequently? How would you optimize the kthSmallest routine?
题目大意
给定一个二叉搜索树,编写一个函数 kthSmallest 来查找其中第 k 个最小的元素。你可以假设 k 总是有效的,1 ≤ k ≤ 二叉搜索树元素个数。
解题思路
- 由于二叉搜索树有序的特性,所以中根遍历它,遍历到第 K 个数的时候就是结果
代码
package leetcode /** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */ func kthSmallest(root *TreeNode, k int) int { res, count := 0, 0 inorder230(root, k, &count, &res) return res } func inorder230(node *TreeNode, k int, count *int, ans *int) { if node != nil { inorder230(node.Left, k, count, ans) *count++ if *count == k { *ans = node.Val return } inorder230(node.Right, k, count, ans) } }