chapter-four/1300~1399/1317.Convert-Integer-to-the-Sum-of-Two-No-Zero-Integers
1317. Convert Integer to the Sum of Two No-Zero Integers
题目
Given an integer n. No-Zero integer is a positive integer which doesn't contain any 0 in its decimal representation.
Return a list of two integers [A, B] where:
AandBare No-Zero integers.A + B = n
It's guarateed that there is at least one valid solution. If there are many valid solutions you can return any of them.
Example 1:
Input: n = 2
Output: [1,1]
Explanation: A = 1, B = 1. A + B = n and both A and B don't contain any 0 in their decimal representation.
Example 2:
Input: n = 11
Output: [2,9]
Example 3:
Input: n = 10000
Output: [1,9999]
Example 4:
Input: n = 69
Output: [1,68]
Example 5:
Input: n = 1010
Output: [11,999]
Constraints:
2 <= n <= 10^4
题目大意
「无零整数」是十进制表示中 不含任何 0 的正整数。给你一个整数 n,请你返回一个 由两个整数组成的列表 [A, B],满足:
- A 和 B 都是无零整数
- A + B = n
题目数据保证至少有一个有效的解决方案。如果存在多个有效解决方案,你可以返回其中任意一个。
解题思路
- 给定一个整数 n,要求把它分解为 2 个十进制位中不含 0 的正整数且这两个正整数之和为 n。
- 简单题。在 [1, n/2] 区间内搜索,只要有一组满足条件的解就 break。题目保证了至少有一组解,并且多组解返回任意一组即可。
代码
package leetcode func getNoZeroIntegers(n int) []int { noZeroPair := []int{} for i := 1; i <= n/2; i++ { if isNoZero(i) && isNoZero(n-i) { noZeroPair = append(noZeroPair, []int{i, n - i}...) break } } return noZeroPair } func isNoZero(n int) bool { for n != 0 { if n%10 == 0 { return false } n /= 10 } return true }